One cheating husband:
If only one man were cheating then clearly his wife would work this out on the
first day as she would have known that no other husbands were cheating and so
the cheating husband must be hers.
Two cheating husbands:
Consider this from the point of view of Bettie one of the wives (Bettie and
Anna) who are being cheated on, though all their positions are infact
the same. Bettie would be aware that Anna's husband was cheating on her and
would therefore expect that she would deduce this on the first day as in the
example above, because this does not happen Bettie knows that Anna is also
aware of a cheating husband. Since Betty was not aware of this it must be her
husband who is cheating. Anna will go through the same thought process and so
two men will be thrown out on the 2nd day.
Three cheating husbands:
Charlotte will be aware Anna and Bettie's cheating husbands and expect the
process to be solved as in the example above on the 2nd
day, when this doesn't happen she
will know that Anna and Bettie must also be aware of 2 cheating husbands and
will hence chuck out her fella on the third day. Anna and Betty will think and do the
same.
N cheating husbands:
Any of the wives being cheated on will be aware of N-1 cheating husbands and
expect the process to be solved on the (N-1)th day,
when this doesn't happen they all become aware that all the other wives that
they thought were being cheated were all under the same impression and hence
they must be the Nth cheated on wife. Hence
on the Nth day N wives throw out N husbands.
Hence the answer, on the 10th
day:
10 men
are thrown out.
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